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"Othe" Riddles - Next 10 of 550.
Riddle:
You are given a set of scales and 12 marbles. The scales are of the old balance variety. That is, a small dish hangs from each end of a rod that is balanced in the middle. The device enables you to conclude either that the contents of the dishes weigh the same or that the dish that falls lower has heavier contents than the other. The 12 marbles appear to be identical. In fact, 11 of them are identical, and one is of different weight. Your task is to identify the unusual marble and discard it. You are allowed to use the scales three times if you wish, but no more. Note that the unusual marble may be heavier or lighter than the others. How can you identify it and determine whether it is heavy or light?
Answer: Number the marbles from 1 to 12. For the first weighing put marbles 1,2,3 and 4 on one side and marbles 5,6,7 and 8 on the other. The marbles will either they balance or not. If they balance, then the different marble is in group 9,10,11,12. Thus, we would put 1 and 2 on one side and 9 and 10 on the other. If these balance then the different marble is either 11 or 12. Weigh marble 1 against 11. If they balance, the different marble is number 12. If they do not balance, then 11 is the different marble. If 1 and 2 vs 9 and 10 do not balance, then the different marble is either 9 or 10. Again, weigh 1 against 9. If they balance, the different marble is number 10, otherwise, it is number 9. That was the easy part. What if the first weighing 1,2,3,4 vs 5,6,7,8 does not balance? Then any one of these marbles could be a different marble. Now, in order to proceed, keep track of which side is heavy for each of the following weighings. Suppose that 5,6,7 and 8 is the heavy side. We now weigh 1,5 and 6 against 2,7 and 8. If they balance, then the different marble is either 3 or 4. Weigh 4 against 9, a known good marble. If they balance then the different marble is 3 or 4. Then, if 1,5 and 6 vs 2,7 and 8 do not balance, and 2,7,8 is the heavy side, then either 7 or 8 is a different, heavy marble, or 1 is a different, light marble. For the third weighing, weigh 7 against 8. Whichever side is heavy is the different marble. If they balance, then 1 is the different marble. Should the weighing of 1,5 and 6 vs 2,7 and 8 show 1,5,6 to be the heavy side, then either 5 or 6 is a different heavy marble or 2 is a light different marble. Weigh 5 against 6. The heavier one is the different marble. If they balance, then 2 is a different light marble.
Riddle:
Two men walk into a restaurant by the sea and sit at the bar. Both men are covered in water. Both men order a plate of Albatross and take one bite. After chewing and swallowing, the first man stands up, walks outside, and shoots himself, while the other finnishes his meal. Why?
Answer: The two men were stranded out in the ocean with a third man when they were beginning to stave. When an albatross landed on their life boat and died they finally had food but it was not enough to feed all three of them. They drew straws and the looser was killed and eaten. They mixed up the human meat and the albatross meat so neither person would know what they were eating. After being rescued, the friends went to eat real Albatross and the man who killed himself realized that he was the one that ate his friend.
Riddle:
The word FACETIOUSLY contains the six vowels, A-E-I-O-U and Y, in their alphabetical order. Can you find another English word that does the same?
Answer: The word is abstemiously. There may be others.
Riddle:
Marco and Bob have been the best friends ever since they were little kids. They are also very competitive. Throughout the years they have challenged each other to do both physical and mental challenges. And they completed the challenge. But one day Marco thought of something to challenge Bob to do - something he could start but never finish. The average man could do it and so could Mark and they were both the same sex and the same size. It is a physical challenge. Can you figure out what it was?
Answer: Marco challenged Bob to get a tan, but he couldn't...Bob is an albino.
Riddle:
There are three guards and three prisoners who need to cross a river. Their boat only holds two people at a time, and the number of prisoners must NEVER be allowed to outnumber the number of guards on either side of the river; otherwise, the prisoners will overpower the guards and, well, the story will come to an abrupt end. List each of the trips that need to be made and who is in the boat, and who is on each of the riverbanks during each trip. How many trips it will take to safely transport all of the guards and prisoners across the river?
Answer: The riddle requires three trips to complete the task!
First trip: G1 and G2 (guard #1 and guard #2) cross the riverSecond trip: P1 (Prisoner #1) and G3 (guard #3) cross the riverThird trip: G1, G2, P2 (Prisoner #2), and P3 (Prisoner #3) cross the river
Riddle:
Robert and David were preparing to have a water balloon fight. "No Fair" cried Robert, "You have 3 times as many as I do!" David said "Fine!" and gave Robert 10 more balloons. "Still not fair!" argued Robert, "You still have twice as many as I do." How many more balloons must David give Robert for them to have the same number?
Answer: David must give Robert another 20 water balloons, giving them each 60. Robert started with 30 water balloons and David with 90.
Riddle:
A car's odometer shows 72927 miles, a palindromic number. What are the minimum miles you would need to travel to form another?
Answer: 110 miles. (73037)
Riddle:
Jack has 8 bricks, 7 of them weigh the same but one is slightly heavier. Using a balance scale, how can Jack find the heavier brick in two weighings?
Answer: First, he splits them into piles of 3, 3, and 2 bricks.
Then, he weighs both groups of 3 with each other. If they balance he knows the brick is one of the 2 unweighed bricks and he can weigh them to find the heavier one.
If the stacks of 3 bricks do not balance, he will weigh 2 of the 3 bricks.
If they balance he will know the brick left unweighed is heavier, or if they do not balance, he will find the heavier one.
Riddle:
There is a man stood on top of a mountain frozen holding a peice of straw. How did he get there?
Answer: He was with his friend in a hotair balloon when they were about to hit a mountin so they took of there clothes to make it lighter so they would go higher but it wasnt working so they drew straws and who ever had the shortest straw would have to jump out so he was the one who picked the shortest straw.
Riddle:
Five baby boomer couples each have one child. Each child is a different age than any of the other children. Each child has a favorite toy which is different from any of the other children's favorite toys. Each family eats at only one fast food restaurant. No two women have the same name and no two men have the same name. The children's names are not known. The child who plays with trains is the youngest. Bill's child plays with a GI Joe. Julie's child likes Pokeman. Mike's family eats at Taco Bell. The family of the 4 year old likes Kentucky Fried Chicken. The oldest child is four years older than Marie's child. The child who plays with Barbie is 8 years old. The child with the age is in the middle, has a mother named Marie. The child in the family that eats at McDonalds has a two year age difference with Larry's child. Carol is the mother in the family that eats at Dairy Queen. The child that plays Nintendo likes Burger King. Steve's child is two years apart in age from the child of the family that eats at Kentucky Fried Chicken. The child that plays with trains is two years apart from the 6 year old. The child that eats at McDonalds is two years older or younger than Regina's child. Lisa's child is 10. Who is married to George?
Answer: Lisa is married to George, and their 10 year old plays with Nintendo. They like to eat at Burger King. The associations are: Child age 4, mother Regina, Father Larry, trains, KFC Child age 6, mother Julie, Father Steve, Pokeman, McDonalds Child age 8, mother Marie, Father Mike, Barbie, Taco Bell Child age 10, mother Lisa, Father George, Nintendo, Burger King Child age 12, mother Carol, Father Bill, GI Joe, Dairy Queen To solve, draw a grid with five rows and five columns. Across the top, above the columns, write Age, Mother, Father, Toy and Food. Figure out the known ages and write them in order in the first column. One child's age is unknown at first. However, once the youngest child is discovered (the one who plays with trains) it is then known that the oldest child is the child with the unknown age. Through additional clues, it is possible to determine that the oldest child is age 12. Take the clue, Lisa?s child is 10. In the mother column corresponding to the age 10, you would write LISA (Maybe circle it, because it is the correct answer.) In the mother column for every other age, write "not Lisa". Do this for each clue. If you know the answer because of a clue, write it in the appropriate column, and then be sure to write "not such and such" in all the other rows for that clue. For example, "The youngest child plays with trains", would result in "not trains" for any child you can tell isn?t the youngest, but you can?t write "trains" for any child, because you don?t know which child is the youngest at first. Eventually, you may find that "mother not Marie" is on every line except one, and then you would know that Marie is the mother on the empty line.
