Enter a keyword into the search box. The riddle search will check to see if the word is in the Title, Riddle, or Answer and return results if they exist.
"Ses" Riddles - Final 9 of 389
Riddle:
Not far off shore a ship stands with a rope ladder hanging over her side. The rope has 10 rungs. The distance between each rung is 12 inches. The lowest rung touches the water. The ocean is calm. Because of the incoming tide, the surface of the water rises 4 inches per hour. How soon will the water cover the third rung from the top rung of the rope ladder?
Answer: When a problem deals with a physical phenonmenon, the phenonmenon should be considered as well as the numbers given. As the water rises, so does the rope ladder. The water will never cover the rung.
Riddle:
Using only brackets, parentheses, and these signs +,-, X, /. How can you express 100 with 5 1's and express 100 three ways with five 5's?
Answer: 111-11=100
(5 x 5 x 5)-(5 x 5)=100; (5+5+5+5)x 5=100;(5 x 5)(5-(5/5)=100.
Riddle:
A boy presses a side of a blue pencil to a side of a yellow pencil, holding both pencils vertically. One inch of the pressed side of the blue pencil, measuring from its lower end, is smeared with paint. The yellow pencil is held steady while the boy slides the blue pencil down 1 inch, continueing to press it against the yellow one. He returns the blue pencil to its former position, then again it slides down 1 inch. He continues until he has lowered the blue pencil 5 times and raised it 5 times- 10 moves in all.
Supposed that during this time the paint neither dries nor diminishes in quantity. How many inches of each pencil will be sneared with paint after the tenth move?
Answer: At the start, 1inch of the yellow pencil gets smeared with wet paint. As the blue pencil is moved downward, a second inch of the blue pencils smears a second inch of the yellow pencil.
Each pair of down and up movesof the blue pencil smears 1 more inch of each pencil. 5 pairs of moves will smear 5 inches. This together with the initial inch, makes 6 inches for each pencil.
Riddle:
Thirty white horses on a red hill, First they champ, Then they stamp, Then they stand still. What are they?
Answer: Teeth.
Riddle:
The king dies and two men, the true heir and an impostor, both claim to be his long-lost son. Both fit the description of the rightful heir: about the right age, height, coloring and general appearance. Finally, one of the elders proposes a test to identify the true heir. One man agrees to the test while the other flatly re-fuses. The one who agreed is immediately sent on his way, and the one who re-fused is correctly identified as the rightful heir. Can you figure out why?
Answer: The test was a blood test. The elder remembered that the true prince was a hemophiliac.
Riddle:
A woman is walking down a street night at a constant pace. As she passes the street light, she notices that her shadow becomes longer. Does the top of her shadow move faster, slower or the same when the shadow is longer as when it is shorter?
Answer: This point maintains a constant speed, independent of the lenght of the shadow.
Riddle:
WYISDERSOMENIMORORSIZASIZDENDERISORSIZ? What does this say?
Answer: Why is there so many more horses asses than there is horses?
Riddle:
Angry and Hungry are two words ending in 'gry" There are three words, (Using popular terminology) in the English Language, that ends in "GRY".
The word is something that everyone uses every day. If you have listened carefully, I have already told you what it is. What is the third word?
Answer: The answer is terminology. It's the third word ending in gry. Using popular terminology
Riddle:
A man told his son that he would give him $1000 if he could accomplish the following task. The father gave his son ten envelopes and a thousand dollars, all in one dollar bills. He told his son, "Place the money in the envelopes in such a manner that no matter what number of dollars I ask for, you can give me one or more of the envelopes, containing the exact amount I asked for without having to open any of the envelopes. If you can do this, you will keep the $1000." When the father asked for a sum of money, the son was able to give him envelopes containing the exact amount of money asked for. How did the son distribute the money among the ten envelopes?
Answer: The contents or the ten envelopes (in dollar bills) should be as follows: $1, $2, $4, $8, $16, $32, $64, $128, $256, $489. The first nine numbers are in geometrical progression, and their sum, deducted from $1,000, gives the contents of the tenth envelope.
Answer explained: The son distributed $1000 into ten envelopes using a clever binary-like approach to ensure he could provide any exact amount from $1 to $1000 by handing over a combination of envelopes without opening them. The first nine envelopes contain amounts that are powers of 2: $1, $2, $4, $8, $16, $32, $64, $128, and $256$, which total $511. The tenth envelope holds the remaining $489 ($1000 - $511$).This setup works because the first nine envelopes can form any amount up to $511 through unique combinations, much like binary numbers. For amounts between $489 and $1000, the son uses the $489 envelope plus a combination of the first nine envelopes to cover the difference—for example, $512 = $489 + $23$, where $23 is made from $16 + $4 + $2 + $1$. This ensures every possible amount from $1 to $1000 can be achieved with a unique combination of envelopes.
Answer explained: The son distributed $1000 into ten envelopes using a clever binary-like approach to ensure he could provide any exact amount from $1 to $1000 by handing over a combination of envelopes without opening them. The first nine envelopes contain amounts that are powers of 2: $1, $2, $4, $8, $16, $32, $64, $128, and $256$, which total $511. The tenth envelope holds the remaining $489 ($1000 - $511$).This setup works because the first nine envelopes can form any amount up to $511 through unique combinations, much like binary numbers. For amounts between $489 and $1000, the son uses the $489 envelope plus a combination of the first nine envelopes to cover the difference—for example, $512 = $489 + $23$, where $23 is made from $16 + $4 + $2 + $1$. This ensures every possible amount from $1 to $1000 can be achieved with a unique combination of envelopes.
