Inless some one can tell me a way that 2 prisoners, at some point, don't out number the guards whether they are just dropping off and still in the boat or actually on land (because even if they are just dropping off and remain in the boat they are still on the other side of the river) I conclude this to be impossible. Please let me know an alternative if you figure one out because i'm stumped.
The two men were stranded out in the ocean with a third man when they were beginning to stave. When an albatross landed on their life boat and died they finally had food but it was not enough to feed all three of them. They drew straws and the looser was killed and eaten. They mixed up the human meat and the albatross meat so neither person would know what they were eating. After being rescued, the friends went to eat real Albatross and the man who killed himself realized that he was the one that ate his friend.
He was with his friend in a hotair balloon when they were about to hit a mountin so they took of there clothes to make it lighter so they would go higher but it wasnt working so they drew straws and who ever had the shortest straw would have to jump out so he was the one who picked the shortest straw.
You turn 2 switches "on" and leave 1 switch "off" and wait about a minute. Then enter the room, but just before you enter, turn one switch from "on" to "off". Once in the room, feel the lightbulb - if it is warm, but off, it has to be the last switch you turned off. If it is on, it has to be the switch left on. If it is cold and is off, it has to be the switch you left in the off position.