Inless some one can tell me a way that 2 prisoners, at some point, don't out number the guards whether they are just dropping off and still in the boat or actually on land (because even if they are just dropping off and remain in the boat they are still on the other side of the river) I conclude this to be impossible. Please let me know an alternative if you figure one out because i'm stumped.
The daughter should pick envelope 1. Unfortunately she picked envelope 3. Statements 1 and 2 were false, and the only true statement was statement 3. If the check was in envelope 1, that would make statement 1 false, statement 2 false and statement 3 is the only true statement. If the check was in envelope 2, statements 1 and 2 would both be true. If the check was in envelope 3, statements 1 and 3 would both be true.
The two men were stranded out in the ocean with a third man when they were beginning to stave. When an albatross landed on their life boat and died they finally had food but it was not enough to feed all three of them. They drew straws and the looser was killed and eaten. They mixed up the human meat and the albatross meat so neither person would know what they were eating. After being rescued, the friends went to eat real Albatross and the man who killed himself realized that he was the one that ate his friend.
The numbers can be grouped by pairs:
999,999,999 and 0;
999,999,998 and 1'
999,999,997 and 2;
and so on....
There are half a billion pairs, and the sum of the digits in each pair is 81. The digits in the unpaired number, 1,000,000,000, add to 1. Then:
(500,000,000 X 81) + 1= 40,500,000,001.