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Riddle: Walking home one day, you take a short cut along the train tracks. The tracks cross a narrow bridge over a deep gorge. At the point you are 3/8 of the way across the bridge, you hear the train whistle somewhere behind you. You charge across the bridge, and jump off the track as the train is about to run you down. As it happens, if you had gone the other way, you would have reached safety just before being run over as well. If you can run ten miles per hour, how fast is the train moving?
Answer: The train is moving at 40 miles per hour. Imagine that a friend is walking with you. When the train whistle blows, you head away from the train, he heads toward it. When he reaches safety, you will be 6/8 (or 3/4)of the way across the bridge, and the train will have just reached the bridge. For the train to cross 4/4 of the bridge in the time you cross the remaining 1/4, the train must be moving four times your speed.
Riddle: Twelve flags stand equidistant along the track at the stadium. The runners start at the first flag. A runner reaches the eighth flag 8 seconds after he starts. If he runs at an even speed, how many seconds does he need altogether to reach the twelfth flag?
Answer: Not 12 seconds. There are 7 segments from the first flag tot the eighth, and 11 from the first to the twelfth. He runs each segment in 8/7 seconds; therefore, 11 segments take 88/7= 12 4/7 seconds.
Riddle: My only timepiece is a wall clock. One day I forgot to wind it and it stopped. I went to visit a friend whos watch is always correct, stayed awhile, and then went home. There I made a simple calculation and set the clock right. How did I do this even though I had no watch on me to tell how long it took me to return from my friend's house?
Answer: Before I left, I wound the wall clock. When I returned, the change in time equaled how long it took to go to my friends house and return, plus the time I spent there. But I knew the latter because I looked at my friends watch when I arrived and left. Subtracting the time of the visit from the time I was absent from my house, and dividing by 2, I obtained the time it took me to return home. I added this time to what my friend watch showed when I left, and set the sum on my wall clock.
Riddle: Granny looked up from her rocking chair and said: As far as I can tell, there is only one anagram of the word trinket. What is it?
Answer: The word knitter.
Riddle: Lazy Larry agreed to work on a job for his brother-in-law for thirty hours at eight dollars an hour, on the condition that he would forfeit ten dollars per hour for every hour that he idled. At the end of the thirty hours Larry wasn't owed any money and didn't owe his brother-in-law any money either. How many hours did Larry work and how many hours did he idle?
Answer: Lazy Larry worked 16-2/3 hours and idled 13-1/3 hours. 16-2/3 hours, at $8.00 an hour amounts to the same amount as 13-1/3 hours at $10.00 per hour.
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Riddle: A house has 6 stories, each the same height. How many times as long is the ascent to the sixth floor as the ascent to the third?
Answer: 2 1/2 times (5/2, not 6/3).
Riddle: A man had a bar of lead that weighed 40 lbs., and he divided it into four pieces in such a way as to allow him to weigh any number of pounds from one to forty. What are the weights of the four pieces?
Answer: 1, 3, 9, 27, are the weights of the four pieces.
Riddle: Try deciphering this code - S T O E E I T A E S S S I N O Y (Hint - count and you will have the answer!)
Answer: Did you count the number of letters? There are 16 of them. Divide them in groups of 4. Then, put each group below the other, and read column wise. Here's how you do it... S T O E E I T A E S S S I N O Y The answer to the code is See it is not so easy.
Riddle: As defendants, we deny all involvement in the unscrupulous dealings which have come to light in the recent government investigation. What country name is hidden in the previous sentence?
Answer: Sweden. "defendants, we deny".
Riddle: A man bumps into his mathematician friend on the street that he hasn't seen in 5 years. The man asks the mathematician how old his children are. The mathematician, who always replies in riddles said, "I now have three children. The sum of their ages is equal to the number of windows on the building in front of you and the product of their ages equals 36." The friend then says "I need one more piece of information." The mathematician then replies "My youngest child has blue eyes." What are the ages of the mathematicians three children?
Answer: They are 6, 6, and 1.
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