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Riddle:

What is the next 3 letters in this riddle? o t t f f s s _ _ _

Answer:

e n t They represent the first letter when writing the numbers one thru ten.

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Riddle:

A camel travels a certain distance each day. Strangely enough, two of its legs travel 30 miles each day and the other two legs travel nearly 31 miles. It would seem that two of the camel's legs must be one mile ahead of the other two legs, but of course this can't be true.

Since the camel is normal, how is this situation possible?

Answer:

The camel operates a mill and travels in a circular clockwise direction. The two outside legs will travel a greater distance than the two inside legs.

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Riddle:

A student zips on his scooter to ride to the train station to get to college. His home is close to two stops; the first one is a mile from home, and the second is two miles from home in the opposite direction. In the morning, he always gets on at the first stop and in the afternoon, he always gets off at the second one.

Why?

Answer:

The sations and his home are on a hill, which allows him to ride down easily on his scooter.

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Riddle:

A boy presses a side of a blue pencil to a side of a yellow pencil, holding both pencils vertically. One inch of the pressed side of the blue pencil, measuring from its lower end, is smeared with paint. The yellow pencil is held steady while the boy slides the blue pencil down 1 inch, continueing to press it against the yellow one. He returns the blue pencil to its former position, then again it slides down 1 inch. He continues until he has lowered the blue pencil 5 times and raised it 5 times- 10 moves in all.

Supposed that during this time the paint neither dries nor diminishes in quantity. How many inches of each pencil will be sneared with paint after the tenth move?

 

Answer:

At the start, 1inch of the yellow pencil gets smeared with wet paint. As the blue pencil is moved downward, a second inch of the blue pencils smears a second inch of the yellow pencil.

Each pair of down and up movesof the blue pencil smears 1 more inch of each pencil. 5 pairs of moves will smear 5 inches. This together with the initial inch, makes 6 inches for each pencil.

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Riddle:

Not far off shore a ship stands with a rope ladder hanging over her side. The rope has 10 rungs. The distance between each rung is 12 inches. The lowest rung touches the water. The ocean is calm. Because of the incoming tide, the surface of the water rises 4 inches per hour. How soon will the water cover the third rung from the top rung of the rope ladder?

Answer:

When a problem deals with a physical phenonmenon, the phenonmenon should be considered as well as the numbers given. As the water rises, so does the rope ladder. The water will never cover the rung.

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Riddle:

The title of the problem tells you how to approach these four questions.

(A).  A bus leaves Moscow for Tula at noon. An hour later a cyclist leaves Tula for mosco, moving slower than the bus. When the bus and cyclist meet, which one of the two will be farther from Moscow?

(B). Which is worth more: a pound of $10 gold peices or half a pound of $20 gold pieces?

(C). At six o'clock the wall clock struck 6 times. Checking with my watch, I noticed the time between the first and last strokes was 30 seconds. How long will the clock take to strike 12 at midnight?

(D). Three swallows fly outward from a point. When will they all be on the same plane in space?

Now check the answers. Did you fall into any of the traps which lurk in these simple problems?

Answer:

(A). Neither

(B). A pound of metal is always more than half a pound of the same metal.

(C). Six strokes took 30 seconds, therefore 12 strokes will take 60 seconds. But when the clock struck six, there were only 5 intervals between strokes, and each interval was 30/5=6 seconds. Between the first and twelfth strokes there will be 11 intervals of 6 seconds each, therefore 12 strokes will take 66 seconds.

(D). There is always a plane that contains any 3 points 

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Riddle:

Two cyclists began a training run, one starting from Moscow and the other starting from Simferopol.

When the riders were 180 miles apart, a fly took an interest. Starting on one cyclists shoulder, the fly flew ahead to meet the other cyclist. After reaching him the fly then turned around and yet back. 

The restless fly continued to shuttleback and fourth until the pair met; then settled on the nose of one rider.

The flys speed was 30 mph. Each cyclist speed was 15 mph.

How many miles did the fly travel?

Answer:

The cyclists took 6 hours to meet. The fly traveled 6*30=180 miles.

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Riddle:

As I traveled up and down our great glorious country, I found myself in a place where the tempature goes up sharply in the day and down at night. This had an effect on my watch, I noticed it was 1/2 a minute faster at nightfall, but at dawn it had lost 1/3 minute, making it only 1/6 minute fast.

One morning- May 1- my watch showed the right time. By what date was it 5 minutes faster?

Answer:

In 24 hours the watch gained 1/2-1/3= 1/6 minute. It would seem it would be 5 minutes fast in 5 X 6= 30 days; that is,the morning of May 31. But already on the morning of May 28 the was 27/6= 4 1/2 minutes fast. At the close of the day the watch gained 1/2 minute more, so it was 5 minutes fast on may 28.

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Riddle:

An alarm clock runs 4 minutes slow every hour. It was set right 3 1/2 hours ago. Now another clock which is correct shows noon. 

In how many minutes, to the nearest minutes, to the nearest minute, will the alarm clock show noon?

Answer:

In 3 1/2 hours the alarm clock has become 14 minutes slow. At noon the alarm clock will fall behind approximently an additional minute. Its hands will show noon in 15 minutes.

 

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Riddle:

(A) Use two digits to make the smallest possible positve intiger.

(B) Five 3s can express 37:  37=33+3+3/3

Find another way to do it.

(C) Use six identical dgits to make 100. (Several solutions are possible.)

(D) Use five 4s to make 55.

(E) Use four 9s to make 20.

Answer:

(A) 1 X 1; 1/1;2/2;ect....;1-0;2-1;and many others.

(B) 37=333/3X3; 37=3 X 3 X 3 + 3/.3

(C) 99 + 99/99; 55+55- 5- 5; (666-66)/6

(D) 44 + 44/4=55.

(E) 9 + 99/9=20.

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