Riddle: I am a two-digit number. All my digits are even. No two digits are the same. None of my digits are prime numbers. I am not a multiple of ten. My tens digit is bigger than my other numbers. If you followed all the previous steps, there should be three options remaining the number is the option where if you add all the digits it's exactly in the middle (in how big the number is) of all the other options with their digits added together. What number am I?

Answer: If you followed all the steps apart from the last one there will be three options remaining: 64, 84, and 86. You then had to add up the digits, 64=6+4=10, 84=8+4=12, and 86=8+6=14. Finally, you then had to take up the middle biggest number (12) and put it back as it was before the digits were added together and your answer should be 84.

Riddle: I am a three-digit number. All of my digits are prime. One of the numbers is even. Each of my numbers are used only once. The total of my first and last digits equals 10. The total of my first two digits equals 5.

Answer: This one is fairly easy if you use elimination if you follow all the first 5 steps you get three options: 525, 327, and 723 but if you followed the last step you would reach your answer. The answer was 327.

Riddle: What is not in me but in you It is at the beginning of the universe Although you can't find it in the whole world In Venus but not Earth Shade doesn't have it but an umbrella does A guitar has it although not a piano. And in a ukulele is the thing that a violin does not have. What is it?