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POW: 03-05-2018

Riddle:

Two travellers spend from 12 o'clock to 6 o'clock walking along a level road, up a hill and back again. Their pace is 4 mph on the level, 3 mph uphill, and 6 mph downhill.


How far do they walk and at what time do they reach the top of the hill?

Answer:

24 miles half past three.

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POW: 02-26-2018

Riddle:

A frog fell into a well 12 feet deep. He could jump 3 feet, but every time he jumped 3 feet, he fell back 2 feet. How many times did he have to jump to get out of the well?

Answer:

The tenth jump took him out. (On the tenth jump he reached 13 feet and was out.)

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POW: 02-19-2018

Riddle:

You are standing in front of a room with one lightbulb inside of it. You cannot see if it is on or off. Outside the room there are 3 switches in the off positions. You may turn the switches any way you want to. You stop turning the switches, enter the room and know which switch controls the lightbulb. How?

Answer:

You turn 2 switches "on" and leave 1 switch "off" and wait about a minute. Then enter the room, but just before you enter, turn one switch from "on" to "off". Once in the room, feel the lightbulb - if it is warm, but off, it has to be the last switch you turned off. If it is on, it has to be the switch left on. If it is cold and is off, it has to be the switch you left in the off position.

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POW: 02-12-2018

Riddle:

What 5 letter word typed in all capital letters can be read the same upside down?

Answer:

SWIMS.

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POW: 02-05-2018

Riddle:

My only timepiece is a wall clock. One day I forgot to wind it and it stopped. I went to visit a friend whos watch is always correct, stayed awhile, and then went home. There I made a simple calculation and set the clock right.


How did I do this even though I had no watch on me to tell how long it took me to return from my friend's house?

Answer:

Before I left, I wound the wall clock. When I returned, the change in time equaled how long it took to go to my friends house and return, plus the time I spent there. But I knew the latter because I looked at my friends watch when I arrived and left.

Subtracting the time of the visit from the time I was absent from my house, and dividing by 2, I obtained the time it took me to return home. I added this time to what my friend watch showed when I left, and set the sum on my wall clock.

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To see more past Problem of the Week's refer to the Riddles Newsletter annals.

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