Find four numbers, the sum of which is 45, so that if 2 is added to the first number, 2 is subtracted from the second number, the third number is multiplied by 2 and the fourth number is divided by 2, then the four numbers so produced are all the same. What are the four numbers?


 8 + 2 = 10

12 - 2 = 10

 5 x 2 = 10

20/45 *  2 = 10

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