Arithmetical Nuts To Crack

Author: Morgan Foster
7 years ago

Riddle: (A) Use two digits to make the smallest possible positive integer. (B) Five 3s can express 37: 37=33+3+3/3 Find another way to do it. (C) Use six identical digits to make 100. (Several solutions are possible.) (D) Use five 4s to make 55. (E) Use four 9s to make 20.
Answer: (A) 1 X 1; 1/1;2/2;ect....;1-0;2-1;and many others. (B) 37=333/3X3; 37=3 X 3 X 3 + 3/.3 (C) 99 + 99/99; 55+55- 5- 5; (666-66)/6 (D) 44 + 44/4=55. (E) 9 + 99/9=20.
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Source: https://www.riddles.com/2293
(A) Use two digits to make the smallest possible positive integer. 
(B) Five 3s can express 37: 37=33+3+3/3 
Find another way to do it. 
(C) Use six identical digits to make 100. (Several solutions are possible.) 
(D) Use five 4s to make 55. 
(E) Use four 9s to make 20.
Arithmetical Nuts to Crack by Morgan Foster v1.


Riddle: (A) Use two digits to make the smallest possible positive integer. 
(B) Five 3s can express 37: 37=33+3+3/3 
Find another way to do it. 
(C) Use six identical digits to make 100. (Several solutions are possible.) 
(D) Use five 4s to make 55. 
(E) Use four 9s to make 20. Answer: (A) 1 X 1; 1/1;2/2;ect....;1-0;2-1;and many others.
(B) 37=333/3X3; 37=3 X 3 X 3 + 3/.3
(C) 99 + 99/99; 55+55- 5- 5; (666-66)/6
(D) 44 + 44/4=55.
(E) 9 + 99/9=20.
by Morgan Foster v2.