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"Word" Riddles - Next 10 of 278.
Riddle: Add a g to my word and I disappear. What word am I ?
Answer: One. When you add a g to one it becomes gone.
Riddle: Spelled forward is a brand of bottled water, spelled backwards is is what you call a person lack of judgement. What word am I?
Answer: Evian, naive.
Riddle: Frank and some of the boys were exchanging old war stories. James offered one about how his grandfather (Captain Smith)led a battalion against a German division during World War I. Through brilliant maneuvers he defeated them and captured valuable territory. Within a few months after the battle he was presented with a sword bearing the inscription: "To Captain Smith for Bravery, Daring and Leadership, World War One, from the Men of Battalion 8." Frank looked at James and said, "You really don't expect anyone to believe that yarn, do you?" What is wrong with the story?
Answer: It wasn't called WWI until much later.
Riddle: Crack this riddle, take the prize; Cheat, and I shall know your lies; For I hide in your words, you see; A bond that begets your honesty. What am I?
Answer: Truth.
Riddle: I am strong as a rock but can be destroyed with one word. What am I?
Answer: Silence.
Riddle: What word does not belong in the following: Cop, Mop chop, or caps?
Answer: Or!
Riddle: I am a three letter word. If you take two letters from me, I am still the same. What word am I?
Answer: The word pea.
Riddle: I am a window, I am a lamp, I am clouded, I am shining, and I am colored; set in white, I fill with water and overflow. I say much, but I have no words. What am I?
Answer: I am an eye.
Riddle: Coffee can go in, but tea cannot.
Riddles can go in, but questions cannot.
Quizzes can go in, but surveys cannot.
Spoons can go in, but forks cannot.
Green can go in, but red cannot.
Glass can go in, but plastic cannot.
Doors can go in, but windows cannot.
Why can some go through the green glass door and others can not?
Answer: Green Glass Door all have double letters. Therefore, only the words with double letters can pass through the Green Glass Door!
Riddle: Before he turned physics upside down, a young Albert Einstein supposedly showed off his genius by devising a complex riddle involving a stolen exotic fish and a long list of suspects. Can you resist tackling a brain teaser written by one of the smartest people in history? Dan Van der Vieren shows how.
Answer: The key is that the person at the back of the line who can see everyone else's hats can use the words "black" or "white" to communicate some coded information. So what meaning can be assigned to those words that will allow everyone else to deduce their hat colors? It can't be the total number of black or white hats. There are more than two possible values, but what does have two possible values is that number's parity, that is whether it's odd or even. So the solution is to agree that whoever goes first will, for example, say "black" if he sees an odd number of black hats and "white" if he sees an even number of black hats. Let's see how it would play out if the hats were distributed like this. The tallest captive sees three black hats in front of him, so he says "black," telling everyone else he sees an odd number of black hats. He gets his own hat color wrong, but that's okay since you're collectively allowed to have one wrong answer. Prisoner two also sees an odd number of black hats, so she knows hers is white, and answers correctly. Prisoner three sees an even number of black hats, so he knows that his must be one of the black hats the first two prisoners saw. Prisoner four hears that and knows that she should be looking for an even number of black hats since one was behind her. But she only sees one, so she deduces that her hat is also black. Prisoners five through nine are each looking for an odd number of black hats, which they see, so they figure out that their hats are white. Now it all comes down to you at the front of the line. If the ninth prisoner saw an odd number of black hats, that can only mean one thing. You'll find that this strategy works for any possible arrangement of the hats. The first prisoner has a 50% chance of giving a wrong answer about his own hat, but the parity information he conveys allows everyone else to guess theirs with absolute certainty. Each begins by expecting to see an odd or even number of hats of the specified color. If what they count doesn't match, that means their own hat is that color. And every time this happens, the next person in line will switch the parity they expect to see.
