3 men go into a motel. The man behind the desk said the room is $30, so each man paid $10 and went to the room. A while later the man behind the

desk realized the room wasonly $25, so he sent the bellboy to the 3 guys' room with $5. on the way the bellboy couldn't figure out how to split

$5 evenly between 3 men, so he gave each man a $1 and kept the other $2 for himself. This meant that the 3 men each paid $9 for the room, which

is a total of $27, add the $2 that the bellboy kept = $29. where is the other dollar?

The three men HAVE paid $27. But the bellboy's $2 are part of it. The hotel has $25 of the men's dollars. The bellboy has the other two. That's $27, and the three the men have make $30. The riddle is confusing because it would add the bellboy's $2 to the men's $27. But the men don't HAVE $27, nine each. They each PAID $9 for a total of $27, of which the hotel has $25 and the bellboy has $2. They HAVE $1 each. Add that to the two the bellboy has, and the $25 in the cash drawer (together the men's $27), and you have accounted for all thirty. I came across this riddle elsewhere on riddles.com, but the answer given was "I don't know"! So I figured it out and posted it.