Riddle: Five baby boomer couples each have one child. Each child is a different age than any of the other children. Each child has a favorite toy which is different from any of the other children's favorite toys. Each family eats at only one fast food restaurant. No two women have the same name and no two men have the same name. The children's names are not known. The child who plays with trains is the youngest. Bill's child plays with a GI Joe. Julie's child likes Pokeman. Mike's family eats at Taco Bell. The family of the 4 year old likes Kentucky Fried Chicken. The oldest child is four years older than Marie's child. The child who plays with Barbie is 8 years old. The child with the age is in the middle, has a mother named Marie. The child in the family that eats at McDonalds has a two year age difference with Larry's child. Carol is the mother in the family that eats at Dairy Queen. The child that plays Nintendo likes Burger King. Steve's child is two years apart in age from the child of the family that eats at Kentucky Fried Chicken. The child that plays with trains is two years apart from the 6 year old. The child that eats at McDonalds is two years older or younger than Regina's child. Lisa's child is 10. Who is married to George?
Answer: Lisa is married to George, and their 10 year old plays with Nintendo. They like to eat at Burger King. The associations are: Child age 4, mother Regina, Father Larry, trains, KFC Child age 6, mother Julie, Father Steve, Pokeman, McDonalds Child age 8, mother Marie, Father Mike, Barbie, Taco Bell Child age 10, mother Lisa, Father George, Nintendo, Burger King Child age 12, mother Carol, Father Bill, GI Joe, Dairy Queen To solve, draw a grid with five rows and five columns. Across the top, above the columns, write Age, Mother, Father, Toy and Food. Figure out the known ages and write them in order in the first column. One child's age is unknown at first. However, once the youngest child is discovered (the one who plays with trains) it is then known that the oldest child is the child with the unknown age. Through additional clues, it is possible to determine that the oldest child is age 12. Take the clue, Lisa?s child is 10. In the mother column corresponding to the age 10, you would write LISA (Maybe circle it, because it is the correct answer.) In the mother column for every other age, write "not Lisa". Do this for each clue. If you know the answer because of a clue, write it in the appropriate column, and then be sure to write "not such and such" in all the other rows for that clue. For example, "The youngest child plays with trains", would result in "not trains" for any child you can tell isn?t the youngest, but you can?t write "trains" for any child, because you don?t know which child is the youngest at first. Eventually, you may find that "mother not Marie" is on every line except one, and then you would know that Marie is the mother on the empty line.
Riddle: A man told his son that he would give him $1000 if he could accomplish the following task. The father gave his son ten envelopes and a thousand dollars, all in one dollar bills. He told his son, "Place the money in the envelopes in such a manner that no matter what number of dollars I ask for, you can give me one or more of the envelopes, containing the exact amount I asked for without having to open any of the envelopes. If you can do this, you will keep the $1000." When the father asked for a sum of money, the son was able to give him envelopes containing the exact amount of money asked for. How did the son distribute the money among the ten envelopes?
Answer: The contents or the ten envelopes (in dollar bills) should be as follows: $1, 2, 4, 8, 16, 32, 64, 128, 256, 489. The first nine numbers are in geometrical progression, and their sum, deducted from 1,000, gives the contents of the tenth envelope.
Riddle: How can the number four be half of five?
Answer: It's true if you think of Roman numerals. FIVE, take away the F and the E and you are left with IV, half of the word FIVE, which is the Roman number for Four.
Difficult Riddles